Termination w.r.t. Q of the following Term Rewriting System could not be shown:
Q restricted rewrite system:
The TRS R consists of the following rules:
f2(g1(X), Y) -> f2(X, f2(g1(X), Y))
Q is empty.
↳ QTRS
↳ Non-Overlap Check
Q restricted rewrite system:
The TRS R consists of the following rules:
f2(g1(X), Y) -> f2(X, f2(g1(X), Y))
Q is empty.
The TRS is non-overlapping. Hence, we can switch to innermost.
↳ QTRS
↳ Non-Overlap Check
↳ QTRS
↳ DependencyPairsProof
Q restricted rewrite system:
The TRS R consists of the following rules:
f2(g1(X), Y) -> f2(X, f2(g1(X), Y))
The set Q consists of the following terms:
f2(g1(x0), x1)
Q DP problem:
The TRS P consists of the following rules:
F2(g1(X), Y) -> F2(X, f2(g1(X), Y))
F2(g1(X), Y) -> F2(g1(X), Y)
The TRS R consists of the following rules:
f2(g1(X), Y) -> f2(X, f2(g1(X), Y))
The set Q consists of the following terms:
f2(g1(x0), x1)
We have to consider all minimal (P,Q,R)-chains.
↳ QTRS
↳ Non-Overlap Check
↳ QTRS
↳ DependencyPairsProof
↳ QDP
↳ QDPAfsSolverProof
Q DP problem:
The TRS P consists of the following rules:
F2(g1(X), Y) -> F2(X, f2(g1(X), Y))
F2(g1(X), Y) -> F2(g1(X), Y)
The TRS R consists of the following rules:
f2(g1(X), Y) -> f2(X, f2(g1(X), Y))
The set Q consists of the following terms:
f2(g1(x0), x1)
We have to consider all minimal (P,Q,R)-chains.
By using an argument filtering and a montonic ordering, at least one Dependency Pair of this SCC can be strictly oriented.
F2(g1(X), Y) -> F2(X, f2(g1(X), Y))
Used argument filtering: F2(x1, x2) = x1
g1(x1) = g1(x1)
f2(x1, x2) = f
Used ordering: Quasi Precedence:
trivial
↳ QTRS
↳ Non-Overlap Check
↳ QTRS
↳ DependencyPairsProof
↳ QDP
↳ QDPAfsSolverProof
↳ QDP
Q DP problem:
The TRS P consists of the following rules:
F2(g1(X), Y) -> F2(g1(X), Y)
The TRS R consists of the following rules:
f2(g1(X), Y) -> f2(X, f2(g1(X), Y))
The set Q consists of the following terms:
f2(g1(x0), x1)
We have to consider all minimal (P,Q,R)-chains.